Calculate the number of neutrons in the remaining atom after emission of an alpha particle from $_{92}^{238} U$ atom.

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Solution

On emission of an alpha particle, the atomic mass is decreased by $4$ units and atomic number by $2$ units.
Atomic mass of daughter element $= 234$
Atomic number of daughter element $= 90$
Number of neutrons $=$ atomic mass $-$ atomic number
$= 234 - 90 = 144$

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Calculate the number of neutrons in the remaining atom after emission of an alpha particle from 23892U atom.

On emission of an alpha particle, the atomic mass is decreased by 4 units and atomic number by 2 units.Atomic mass of daughter element =234Atomic number of daughter element =90Number of neutrons = atomic mass − atomic number =234−90=144

Calculate the number of neutrons in the remaining atom after emission of an alpha particle from $_{92}^{238} U$ atom.

On emission of an alpha particle, the atomic mass is decreased by $4$ units and atomic number by $2$ units.
Atomic mass of daughter element $= 234$
Atomic number of daughter element $= 90$
Number of neutrons $=$ atomic mass $-$ atomic number
$= 234 - 90 = 144$