1
Question
Calculate the number of neutrons in the remaining atom after emission of an alpha particle from 23892U atom.
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Solution
On emission of an alpha particle, the atomic mass is decreased by 4 units and atomic number by 2 units.
Atomic mass of daughter element =234Atomic number of daughter element =90
Number of neutrons = atomic mass − atomic number
=234−90=144
Atomic mass of daughter element =234
Atomic number of daughter element =90
Number of neutrons = atomic mass − atomic number
=234−90=144
Number of neutrons = atomic mass − atomic number
=234−90=144
Suggest Corrections
0
by
fast neutrons. In one fission event, no neutrons are emitted and the
final end products, after the beta decay of the primary fragments,
are
and
.
Calculate Q for this fission process. The relevant atomic and
particle masses are
=238.05079 u
=139.90543 u
= 98.90594 u