Since 1 mole of Na2CO3.10H20 = 6.022 X1023molecules of Na2CO3.10H20
So 0.1 mol of Na2CO3.10H2O will have = 6.022 X1023 X0.1 molecules of Na2CO3.10H20
Now we know that each molecule contains 13 O-atoms,
Total no. of O- atoms = 6.022 X1022 X 13
Calculate the number of (a) Oxygen atoms in 0.10 mole of Na2CO3. 10H2O (b) gram atoms in 4.6 gram of sodium.