Calculate the number of oxygen atoms in 0.10 mole of Na2 Co3 . 10H2O

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Solution

Since 1 mole of Na2CO3.10H20 = 6.022 X1023molecules of Na2CO3.10H20

So 0.1 mol of Na2CO3.10H2O will have = 6.022 X1023 X0.1 molecules of Na2CO3.10H20

Now we know that each molecule contains 13 O-atoms,

Total no. of O- atoms = 6.022 X1022 X 13

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{N a}_{2} {C O}_{3} \cdot 10 H_{2} O

Calculate the number of
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(b) gram atoms in 4.6 gram of sodium.

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N a_{2} C O_{3} \cdot 10 H_{2} O

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{N a}_{2} S_{2} O_{3}

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