Calculate the number of oxygen atoms in 88 g $C O_{2}$ . What would be the mass of CO having the same number of oxygen atoms ?

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Solution

$88 g C O_{2} =$ 2 moles of $C O_{2}$ . One molecule consists of 2 oxygen atoms.
No. of oxygen atoms $= 2 \times 2 \times 6.02 \times 10^{23} = 24.08 \times 10^{23}$
CO molecule has one oxygen atom.
Mass of CO containing $24.08 \times 10^{23}$ oxygen atoms
$= \frac{28}{6.02 \times 10^{23}} \times 24.08 \times 10^{23} = 112 g$

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