Question

Calculate the number of peroxy linkage(s) in $H_2{S}_2{O}_8$.

• A. 2
• B. \N
• C. 1
• D. None of the above

Answer 1

The correct option is C 1

$H_2{S}_2{O}_8$, number of central atom = 1
$\text{Number of peroxy linkage}=\frac{\text{Calculated oxidation state - Maximum oxidation state}}{2}$
Consider the oxidation state of S as 'x' in $H_2{S}_2{O}_8$
$\therefore 2x+8\times (-2)+2=0$
$\Rightarrow x=+7$
Thus calculated oxidation state of S = +7
Maximum oxidation of sulphur = number of valence electron = +6
$\therefore \text{Number of peroxy linkage}=\frac{7-6}{1}$
$\Rightarrow \text{Number of peroxy linkage}=1$