Calculate the oxidation number of underlined elements in the following compounds:
$C r - - O_{2} C l_{2}$

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-4

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Solution

The correct option is C 6
Let oxidation number of Cr be 'x' in $C r O_{2} C l_{2}$
$charge on C l = - 1$
$charge on O = - 2$
$x - 2 \times 2 + 2 \times (- 1) = 0$
$x = + 6$

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