Question

Calculate the percentage composition of the different atoms in one mole potassium chlorate.

Answer 1

Potassium chlorate is $KCl{O}_3$

% of atom $X$ in $KCl{O}_3=\frac{\text{(number of}X\text{atoms)}\times \text{(Atomic weight of}X)}{\text{Molecular weight of}KCl{O}_3}\times 100$

For $X=K$, % $K=\frac{1\times 39}{122.5}\times 100=31.83$%

For $X=Cl$, % $Cl=\frac{1\times 35.5}{122.5}\times 100=28.98$%

For $X=O$, % $O=\frac{3\times 16}{122.5}\times 100=39.19$%