Calculate the percentage of carbon in a 55 % pure sample of calcium carbonate.
$(C a = 40, C = 12, O = 16)$

4.3%

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5.6%

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6.6%

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None of the above

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Solution

The correct option is C 6.6%
Let mass of sample is 100 gm,
mass of $C a C O_{3} = 55 g m$
mass of $C$ $= 12 \times \frac{55}{100} = 6.6 g m$ . So % of $C$ in sample $= 6.6$ %.

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