Calculate the percentage of Nitrogen in the fertilizer, Ammonium Nitrate $N H_{4} N O_{3}$

[H = 1, N = 14, O = 16]

35%

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40%

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20%

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10%

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Solution

The correct option is A
35%

Molecular weight of $N H_{4} N O_{3}$

= 14 + 4 + 14 + 48

= 10 + 14 + 48

= 32 + 48

= 80g (approx)

Amount of Nitrogen in $N H_{4} N O_{3} = 2 \times 14$

= 28

$∴$ Percentage of Nitrogen $= \frac{28}{80} \times 100$

= 35 %

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Similar questions

The usefulness of a fertilizer depends upon percentage of nitrogen present in it. Find which of the following is a better fertilizer:
(a) ammonium nitrate [NH₄NO₃]
(b) ammonium phosphate [(NH₄)₃PO₄]
(N = 14, H = 1, O = 16, P = 31)

Calculate the percentage of nitrogen and oxygen in ammonium nitrate.

[Relative molecular mass of ammonium nitrate is 80, H = 1, N= 14, 0= 16],

Urea is a very important nitrogenous fertilizer. Its formula is $C O N_{2} H_{4}$ Calculate the percentage of nitrogen in urea (C = 12, O = 16, N = 14 and H = 1).

Q. If the relative molecular mass of ammonium nitrate is 80, the percentage of nitrogen and oxygen in ammonium nitrate is:

[N = 14, H = 1, O = 16]

Calculate the percentage composition of nitrogen in $N H_{4} N O_{3} .$

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Calculate the percentage of Nitrogen in the fertilizer, Ammonium Nitrate NH4NO3 [H = 1, N = 14, O = 16]

The correct option is A 35% Molecular weight of NH4NO3 = 14 + 4 + 14 + 48 = 10 + 14 + 48 = 32 + 48 = 80g (approx) Amount of Nitrogen in NH4NO3=2×14 = 28 ∴ Percentage of Nitrogen =2880×100 = 35 %

Calculate the percentage of Nitrogen in the fertilizer, Ammonium Nitrate $N H_{4} N O_{3}$

[H = 1, N = 14, O = 16]

The correct option is A
35%

Molecular weight of $N H_{4} N O_{3}$

= 14 + 4 + 14 + 48

= 10 + 14 + 48

= 32 + 48

= 80g (approx)

Amount of Nitrogen in $N H_{4} N O_{3} = 2 \times 14$

= 28

$∴$ Percentage of Nitrogen $= \frac{28}{80} \times 100$

= 35 %