Calculate the percentage of sodium in sodium aluminium fluoride Na3AlF correct to the nearest whole number-F- 19- Na- 23- Al-27

Step 1: Write the given terms:F= 19g Na= 23g Al=27gStep 2: Find the percentage:Molar mass of Na3AlF= (3x23) + 27 + (6x19) = 210 gmNow, percentage of N ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Ideal Gas Equation

Calculate the...

Question

Calculate the percentage of sodium in sodium aluminium fluoride (Na₃AlF) correct to the nearest whole number.
(F= 19; Na= 23; Al=27)

Open in App

Solution

Step 1: Write the given terms:
F= 19g Na= 23g Al=27g
Step 2: Find the percentage:
Molar mass of Na₃AlF= (3x23) + 27 + (6x19) = 210 gm
Now, percentage of Na= 69g x $\frac{100}{210 g}$ = 33%
Step 3: Result:
Hence, the percentage of Na in Na₃AlF is 33%

Suggest Corrections

Similar questions

(a) Calculate the percentage of sodium in sodium aluminium fluoride (Na₃AIF₆) correct to the nearest whole number. (F = 19; Na = 23; Al = 27)
(b) 560 ml of carbon monoxide is mixed with 500 ml of oxygen and ignited. The chemical equation for the reaction is as follows:
2CO + O₂ $\overset{}{\to}$ 2CO₂
Calculate the volume of oxygen used and carbon dioxide formed in the above reaction.

Q. Calculate the formula masses of the following compounds:
(a) Sodium oxide, Na₂O
(b) Aluminium oxide, Al₂O₃
(Given: Atomic Masses: Na = 23 u; O = 16 u; Al = 27 u)

Q. The percentage of sodium in sodium aluminium fluoride

[N a_{3} A l F_{6}]

correct to the nearest whole number is:

[

F = 19; N a = 23; A l = 27

]

Calculate the percentage of sodium in sodium aluminum fluoride.
([Na₃AlF₆] correct to the nearest whole number).
(F= $19$ ; Na = $23$ ; AI = $27$ )

Calculate the percentage of sodium in sodium aluminium fluoride (Na₃AlF₆) correct to the nearest whole number.

(F= 19,Na = 23,Al = 27).

Join BYJU'S Learning Program

Calculate the percentage of sodium in sodium aluminium fluoride (Na3AlF) correct to the nearest whole number.(F= 19; Na= 23; Al=27)

Step 1: Write the given terms:F= 19g Na= 23g Al=27gStep 2: Find the percentage:Molar mass of Na3AlF= (3x23) + 27 + (6x19) = 210 gmNow, percentage of Na= 69g x 100210g = 33%Step 3: Result:Hence, the percentage of Na in Na3AlF is 33%

Calculate the percentage of sodium in sodium aluminium fluoride (Na₃AlF) correct to the nearest whole number.
(F= 19; Na= 23; Al=27)

Step 1: Write the given terms:
F= 19g Na= 23g Al=27g
Step 2: Find the percentage:
Molar mass of Na₃AlF= (3x23) + 27 + (6x19) = 210 gm
Now, percentage of Na= 69g x $\frac{100}{210 g}$ = 33%
Step 3: Result:
Hence, the percentage of Na in Na₃AlF is 33%