Question

Calculate the percentage of sulphur present in sulphuric acid $\left(H_{2}S{O}_4\right)$.

Answer 1

We know that the molar mass of $H_{2}S{O}_4=98\text{g}$
Mass of sulphur in $H_{2}S{O}_4=32\text{g}$
$\text{\% of sulphur}=\frac{\text{mass of sulphur}}{\text{total mass of the compound}}\times 100=\frac{32}{98}\times 100=32.65\%$