The number of moles of sulphuric acid present in $24.5$ g of $H_{2} S O_{4}$ is:

2.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.25

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C 0.25
Number of moles $= \frac{W e i g h t}{M o l e c u l a r w e i g h t}$

$= \frac{24.5}{98} =$ $0.25$ .

Suggest Corrections

Similar questions

The number of moles present in $24.5 g m s$ of $H_{2} S O_{4}$ is

(H_{2} S O_{4})

H_{2} S O_{4}

H_{2} S O_{4}

0.2

H_{2} S O_{4}

Join BYJU'S Learning Program