Number of g moles of sulphur present in 49 g of $H_{2} S O_{4}$ are:

0.5

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0.05

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0.063

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0.126

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Solution

The correct option is A 0.5
$M o l e s = \frac{W e i g h t}{G M w t}$

$M o l e s = \frac{49}{98}$ = 0.5 mol

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