Question

Calculate the $pH$ of $0.01\text{M}{H}_{2}S{O}_4$.

• A. $2$
• B. $2.3$
• C. $1.7$
• D. $0.3$

Answer 1

The correct option is C $1.7$

The concentration of $H^{+}$ in the $0.01\text{M}{H}_{2}S{O}_4$ is $=\left[H^{+}\right]=2\times 0.01=2\times {10}^{-2}$
$\therefore pH=-\log \left(H^{+}\right)=-\log (2\times {10}^{-2})=2-0.3=1.7$