Question

Calculate the position of the centre of mass of a system consisting of two particles of masses $m_1$ and $m_2$ separated by a distance L apart.

Answer 1

Position of center of mass $X_{cm}=\frac{m_1{x}_1+m_2{x}_2}{m_1+m_2}$

Let the origin to the position of $m_1$ i.e. $x_1=0$

$⟹x_2=L$

Or $X_{cm}=\frac{0+m_{2}L}{m_1+m_2}=\frac{m_{2}L}{m_1+m_2}$