Calculate the power loss in an electric transmission cable15 km long, carrying a current of 100A at a potential of 200 kV. The resistance per km of the cable is 0.2 ohms

Open in App

Solution

I = 100 A

Cable of 1 km has resistance = 0.2 ohm

Cable of 15 km will have resistance = 0.2 * 15 = 3 ohm

Power loss = I²* R = 100²* 3 = 30000 Watt

Answer : 30000 Watt

Suggest Corrections

Similar questions

.Calculate the power loss in an electrical transmission cable, 15 km long, carrying a current of 100A at a potential of 200 kV. The resistance per km of the cable is 0.2 Ω.

Q. A town situated

20 k m

away from a power house at

440 V

, requires

600 K W

of electric power at

220 V

. The resistance of transmission line carrying power is

0.4 Ω

per km. The town gets power from the line through a

3000 V - 220 V

step down transformer at a substation in the town. Which of the following is /are correct

Q. A thermal power plant produces electric power of

500 k W

2500 V

. The electrical energy is transported

200 k m

away for distribution at

240 V

.
If the resistance of the transmission cable is

0.025 Ω / k m

, how much will be the current in the distribution line?

Q. If the direct transmission method with a cable of resistance

0.4 Ω k m^{- 1}

is used, the power dissipation (in %) during transmission is

Q. A 1 km long voltage transmission line has a voltage 400 volts. If the current carrying wire has resistance 0.2

Ω

/meterthen how much electrical energy(in joules) will be lost in 0.5 seconds through the whole transmission line?

Join BYJU'S Learning Program

Calculate the power loss in an electric transmission cable15 km long, carrying a current of 100A at a potential of 200 kV. The resistance per km of the cable is 0.2 ohms

I = 100 A Cable of 1 km has resistance = 0.2 ohm Cable of 15 km will have resistance = 0.2 * 15 = 3 ohm Power loss = I2 * R = 1002 * 3 = 30000 Watt Answer : 30000 Watt

I = 100 A

Cable of 1 km has resistance = 0.2 ohm

Cable of 15 km will have resistance = 0.2 * 15 = 3 ohm

Power loss = I²* R = 100²* 3 = 30000 Watt

Answer : 30000 Watt