Calculate the pressure at a depth of $50 m$ below sea level.

Given:
Density of sea water = $1024 k g / m^{3}$ .
And, acceleration due to gravity $g = 10 m / s^{2}$

$512000 P a$

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$51200 P a$

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$5120 P a$

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$512 P a$

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Solution

The correct option is A
$512000 P a$

The expression of pressure at the bottom of a liquid of height $h$ and density $ρ$ is given by $ρ g h$ .
The given values are:
$ρ = 1024 k g / m^{3}$ , $h = 50 m$ and $g = 10 m / s^{2}$ .
Thus, $p r e s s u r e = ρ g h = 1024 \times 50 \times 10 = 512000 P a$ .

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Calculate the pressure at a depth of $50 m$ below sea level.

Given:
Density of sea water = $1024 k g / m^{3}$ .
And, acceleration due to gravity $g = 10 m / s^{2}$

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Calculate the pressure at a depth of 50 m below sea level. Given: Density of sea water = 1024 kg/m3. And, acceleration due to gravity g=10 m/s2

The correct option is A 512000Pa The expression of pressure at the bottom of a liquid of height h and density ρ is given by ρgh. The given values are: ρ=1024 kg/m3, h=50 m and g=10 m/s2. Thus, pressure=ρgh=1024×50×10=512000Pa.

Calculate the pressure at a depth of $50 m$ below sea level.

Given:
Density of sea water = $1024 k g / m^{3}$ .
And, acceleration due to gravity $g = 10 m / s^{2}$