Calculate the pressure at a depth of $50 m$ below the surface of the sea. The density of sea water $ρ$ is $1024$ $k g m^{- 3}$ .

612000 P a

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51200 P a

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5120 P a

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512 P a

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Solution

The correct option is A $612000 P a$
The expression of pressure at the bottom of a liquid of height $h$ and density $ρ$ is given by $P_{o} + ρ g h$ .
The given values are:
$ρ = 1024 k g m^{- 3}$
$h = 50 m$
$g = 10 m s^{- 2}$ .
$P_{o} = 10^{5} P a$

Substituting values, pressure:
$P = P_{o} + ρ g h$
$P = 10^{5} + 1024 \times 50 \times 10$
$P = 612000 P a$ .

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