Calculate the pressure at a depth of 50m below the surface of the sea. The density of sea water is 1024 $\frac{k g}{m^{3}}$ .

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Solution

Depth of the point = 50 m

Density of sea water = 1024 $\frac{k g}{m^{3}}$

Acceleration due to gravity = g = 10 $\frac{m}{{s e c}^{2}}$

Pressure = Depth * Density of water * Acceleration due of gravity

=50 * 10 * 1024

Pressure = 512000 $\frac{N}{m^{2}}$ or Pascals

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Calculate the pressure at a depth of $50 m$ below the surface of the sea. The density of sea water is $1024 k g / m^{3}$ . Take acceleration due to gravity $g = 10 m / s^{2}$

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Calculate the pressure at a depth of 50m below the surface of the sea. The density of sea water is 1024 kgm3. __

Depth of the point = 50 m Density of sea water = 1024 kgm3 Acceleration due to gravity = g = 10msec2 Pressure = Depth * Density of water * Acceleration due of gravity =50 * 10 * 1024 Pressure = 512000 Nm2 or Pascals

Calculate the pressure at a depth of 50m below the surface of the sea. The density of sea water is 1024 $\frac{k g}{m^{3}}$ .

__

Depth of the point = 50 m

Density of sea water = 1024 $\frac{k g}{m^{3}}$

Acceleration due to gravity = g = 10 $\frac{m}{{s e c}^{2}}$

Pressure = Depth * Density of water * Acceleration due of gravity

=50 * 10 * 1024

Pressure = 512000 $\frac{N}{m^{2}}$ or Pascals