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Question

Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the Van der Waals constant a = 3.592 dm6 atm mol−2. Assume that the volume occupied by CO2 molecules is negligible.

A

0.8422 atm

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B

0.9922 atm

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C

1.2 atm

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D

1.1652 atm

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Solution

The correct option is B

0.9922 atm

The Van der Waals equation for 1 mol of gas is given by:

(p+aV2)/(V−b)=RT

The volume occupied by CO2 molecules is negligible implies that b = 0. Substituting given values and considering V = 22.4 L for 1 mol of gas at 1 atm, we get

p=RTV−aV2=0.082×273/22.4−3.592/22.42

= 0.9922 atm


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