Calculate the pressure exerted by one mole of CO2 gas at 273 K, if the Van der Waals constant a = 3.592 dm6 atm mol−2. Assume that the volume occupied by CO2 molecules is negligible.
The correct option is B
0.9922 atm
The Van der Waals equation for 1 mol of gas is given by:
(p+aV2)/(V−b)=RT
The volume occupied by CO2 molecules is negligible implies that b = 0. Substituting given values and considering V = 22.4 L for 1 mol of gas at 1 atm, we get
p=RTV−aV2=0.082×273/22.4−3.592/22.42
= 0.9922 atm