Calculate the pressure exerted by the waters of the Bay of Bengal near Puducherry (density = 1025 kg/m3) at a depth of 11.0 Km.

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Solution

Pressure = hρg.
Where h=depth=11 km = 11000m
ρ=density=1025 kg/m^3
g=9.8 m/s^2

pressure = 11000x1025x9.8=1.1 x 10^8 N/m^2

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Calculate the pressure at a depth of 50m below the surface of sea. The density of sea water is 1024 $\frac{k g}{m^{3}}$ .

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