Calculate the quantity of heat required to convert 10 kg of ice at 0- C into water at the same temperature- Latent heat of fusion of ice -335 - 103 J - kg A- 33-5 kJB- 33-5 kJC- 3350 kJD- 3-35 kJ

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Specific Heat Capacity

Calculate the...

Question

Calculate the quantity of heat required to convert 10 kg of ice at $0^{\circ} C$ into water at the same temperature.
(Latent heat of fusion of ice $- 335 \times 10^{3} J / k g$ )

33.5 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

33.5 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3350 kJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.35 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 3350 kJ
We know, $Q = m L_{f}$
(where Q - quantity of heat required, m - mass, $L_{f}$ - latent heat of fusion.)
Given m = 10 kg
$L_{f} = 335 \times 10^{3} J / k g$
Quantity of heat required $= m L_{f}$
$= 10 \times 335 \times 10^{3}$
$= 3350 \times 10^{3}$
$= 3350 k J$

Suggest Corrections

Similar questions

Q. Calculate the quantity of heat required to convert

10 k g

of ice at

0^{o} C

to water at

50^{o} C

(Specific heat of water is

4200 J / k g^{o} C

, Latent heat of fusion of ice is

336 \times 10^{3} J / k g

)

Q. In a process, 10 gm of ice at

- 5^{o} C

is converted into steam at

100^{o} C

.If latent heat of fusion of ice is 80 cal

g^{- 1}

, then the amount of heat required to convert 10 g of ice at

0^{\circ} C

into 10 g of water at same temperature is :

A piece of ice of mass 40 g is dropped into 200 g of water at 50 $^{\circ} C$ . Calculate the final temperature of the water after all the ice has melted. (Specific heat capacity of water = 4200 J/kg $^{\circ} C$ , specific latent heat of fusion of ice $= 336 \times 10^{3}$ J/kg)

Q. M g of ice at 0

^{o}

C is to be converted to water at 0

^{o}

C. If L is the latent heat of fusion of ice, the quantity of heat required for the above operation would be:

Q. Calculate the quantity of heat required to convert 10 kg of ice at

0^{\circ}

to water at

50^{\circ} C

would be. Specific heat of water is 4200 J/kg

^{\circ} C

Join BYJU'S Learning Program

Calculate the quantity of heat required to convert 10 kg of ice at 0∘C into water at the same temperature. (Latent heat of fusion of ice −335×103J/kg)

The correct option is C 3350 kJWe know, Q=mLf (where Q - quantity of heat required, m - mass, Lf - latent heat of fusion.) Given m = 10 kg Lf=335×103 J/kg Quantity of heat required =mLf =10×335×103 =3350×103 =3350 kJ

Calculate the quantity of heat required to convert 10 kg of ice at $0^{\circ} C$ into water at the same temperature.
(Latent heat of fusion of ice $- 335 \times 10^{3} J / k g$ )

The correct option is C 3350 kJ
We know, $Q = m L_{f}$
(where Q - quantity of heat required, m - mass, $L_{f}$ - latent heat of fusion.)
Given m = 10 kg
$L_{f} = 335 \times 10^{3} J / k g$
Quantity of heat required $= m L_{f}$
$= 10 \times 335 \times 10^{3}$
$= 3350 \times 10^{3}$
$= 3350 k J$