Question

calculate the radius of the second orbit of li+ ion

Answer 1

Dear Student,

​$$\begin{gathered} \mathrm{Radius}\mathrm{of}\mathrm{orbit},\mathrm{r}=0.529\times \frac{{\mathrm{n}}^2}{\mathrm{Z}}\stackrel{°}{\mathrm{A}} \\ \mathrm{Here},\mathrm{n}=2 \\ \mathrm{Z}=3 \\ \mathrm{or},\mathrm{r}=0.529\times \frac{2^2}{3}=0.7053\stackrel{°}{\mathrm{A}}=70.53\mathrm{pm} \end{gathered}$$