Calculate the radius of the smallest orbit of hydrogen atom.

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Solution

Dear Student ,
Using the equation ,
$r_{n} = n^{2} \frac{a_{0}}{Z^{2}} = 1^{2} \times \frac{0 \cdot 53}{1^{2}} = 0 \cdot 53 \overset{0}{A}$
Regards

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Calculate the radius of the smallest orbit of hydrogen atom.

Dear Student , Using the equation , rn=n2a0Z2=12×0·5312=0·53 A0 Regards

Dear Student ,
Using the equation ,
$r_{n} = n^{2} \frac{a_{0}}{Z^{2}} = 1^{2} \times \frac{0 \cdot 53}{1^{2}} = 0 \cdot 53 \overset{0}{A}$
Regards