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Relating Translational KE and T

Calculate the...

Question

Calculate the ratio of average K.E of one molecule of diatomic (rigid) and diatomic (elastic)at temperature $150^{o} C$ .

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Solution

Average K.E is a result of transitional and rotational energies.
For rigid molecule, $K . E_{a v g} = \frac{3}{2} K_{b} T$
For elsatic molecule, $K . E_{a v g} = 5 K_{b} T$
$∴$ ratio= $\frac{3}{10} = 0.3$ .

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Relating Translational KE and T

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