Calculate the ratio of pH of a solution containing 1 mole of CH3COONa+1 of HCl per litre and of the other solution containing 1 mole of CH3COONa+1 mole of CH3COOH per litre.
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Solution
1st case: CH3COONa+HCl⟶CH3COOH+NaCl
As we know for weak acid pH=12(pKa−logC)
C=1 M
So pH1=−12logKa 2nd case: pH2=−logKa+log[Salt][Acid]