Calculate the ratio of the velocity of light and the velocity of electron in the $2$ nd orbit of a hydrogen atom. (Given $h = 6.624 \times 10^{- 27} e r g - s e c$ ; $m = 9.108 \times 10^{- 28} g$ ; $r = 2.11 \times 10^{- 8} c m$ ).

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Solution

Velocity of electron in $2^{n d}$ orbit $= 2.18 \times 10^{6} \times \frac{1}{2} = 1.09 \times 10^{6} m / s$ $m / s$
Required ration $= \frac{3 \times 10^{8}}{1.09 \times 10^{6}} = 275.23$

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