Calculate the reasonance energy of N2O from the following data-of Hfo N2O - 82 kJ mol-1Bond energy of N - N- N - N- O - O and N - O bonds are 946- 418- 498 607 kJ mol-1 respectively-

N ≡ N (g) + 1/2(O = O) → N = N = O(g) H_f(N_2O)= [ H_(N≡ N) + 1/2 H_(O=O)] [ H_(N=O) + H_(N=N)] = [946 + 1/2× 498] (607 + 418) = 946 + 249 607 ...

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Calculate the reasonance energy of $N_{2} O$ from the following data.of $△ H_{f}^{o}$ $N_{2} O = 82 k J m o l^{- 1}$

Bond energy of N $\equiv$ N, N = N, O = O and N = O bonds are 946, 418, 498 & 607 $k J m o l^{- 1}$ respectively.

80 kJ

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85 kJ

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88 kJ

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90 KJ

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N_{2} O

△_{f} H^{o} o f N_{2} O = 82 k J m o l^{- 1},

N \equiv N, 946 k J m o l^{- 1}; N = N, 418 k J m o l^{- 1};

O = O, 498 k J m o l^{- 1}; N = O, 607 k J m o l^{- 1}

N_{2} O

Δ H_{f}^{\circ}

N_{2} O = 82 k J m o l e^{- 1}

N \equiv N

N = N

O = O

N = O

m o l e^{- 1}

N_{2} O

Δ H_{f}

N_{2} O = 82 k J {m o l}^{- 1}

N \equiv N

N \equiv N

O \equiv O

N \equiv O

K J {m o l}^{- 1}

N_{2} O (i n k J m o l^{- 1})

Δ H_{f}^{0}

N_{2} O

82 k J m o l^{- 1}

N \equiv N 946 k J m o l^{- 1}

N = N 418 k J m o l^{- 1}

O = O 498 k J m o l^{- 1}

N = O 607 k J m o l^{- 1}

N_{2} O

(Δ H_{f}^{o}

N_{2} O = 82 k J m o l^{- 1})

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