Calculate the rms speed of O2 at 273K and 1×104Pa pressure. The density of O2 under these conditions is 1.50kg m−3.
A
2×104m s−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5×102m s−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
141.42m s−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
943.6m s−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C141.42m s−1 As urms=√3RTM
using PV=nRT urms=√3PVnM urms=√3PV×Mw×M urms=√3PVw urms=√3Pd
where, density d=wV
therefore,
urms=√3Pd=√3×1041.50=141.42m s−1