Calculate the rms speed of nitrogen at STP pressure - 1 atm and temperature - 0- C- The density of nitrogen in these conditions is 1-25 kg m-3-

At STP, the pressure is 1.0 × 10^5 N m^ 2. The rms speed is v_rms = √(3p/ρ) = √(3 × 10^5 Nm^ 2/1.25 kg m 3) = 490 ms^ 1. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XI

Physics

RMS and KE Expressions

Calculate the...

Question

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

490 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

510 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

410 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

370 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
490 m/s

At STP, the pressure is $1.0 \times 10^{5} N m^{- 2}$ . The rms speed is

$v_{r m s} = \sqrt{\frac{3 p}{ρ}}$

$= \sqrt{\frac{3 \times 10^{5} N m^{- 2}}{1.25 k g m - 3}}$

$= 490 m s^{- 1}$ .

Suggest Corrections

Similar questions

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

Q. The rms speed of

N_{2}

molecular at STP (P=1 tm; T=

0^{0} C

) is.....
(the density of

N_{2}

in these conditions is 1.25

{k g / m}^{3}

Q. The densities of nitrogen and oxygen at NTP are

1.25 k g / m^{3}

and

1.43 k g / m^{3}

respectively .If the speed of sound in oxygen at NTP is 320 m/s. calculate the speed in nitrogen, under the same conditions of temperature and pressure. (y for both the gases is 1.4)

Q. Calculate the rms speed of

O_{2}

273 K

and

1 \times 10^{4} Pa

pressure. The density of

O_{2}

under these conditions is

1.50 {kg m}^{- 3}

Q. At

0^{\circ} C

and 1.0 atm

(= 1.01 \times 10^{5} N / m^{2})

pressure the densities of air, oxygen and nitrogen are

1.284 k g / m^{3}, 1.429 k g / m^{3}

and

1.251 k g / m^{3}

respectively. Calculate the percentage of nitrogen in the air from these data, assuming only these two gases to be present.

Join BYJU'S Learning Program

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = 0∘C). The density of nitrogen in these conditions is 1.25 kg m−3.

The correct option is A 490 m/s At STP, the pressure is 1.0×105 N m−2. The rms speed is vrms=√3pρ =√3×105Nm−21.25 kg m−3 =490 ms−1.

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

The correct option is A
490 m/s

At STP, the pressure is $1.0 \times 10^{5} N m^{- 2}$ . The rms speed is

$v_{r m s} = \sqrt{\frac{3 p}{ρ}}$

$= \sqrt{\frac{3 \times 10^{5} N m^{- 2}}{1.25 k g m - 3}}$

$= 490 m s^{- 1}$ .