The rms speed of $N_{2}$ molecular at STP (P=1 tm; T= $0^{0} C$ ) is.....
(the density of $N_{2}$ in these conditions is 1.25 ${k g / m}^{3}$

493 m/s

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390 m/s

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290 m/s

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590 m/s

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Solution

The correct option is A 493 m/s
Given,
$P = 1.013 \times 10^{5} P a$
$T = 273.15 K$
$ρ = 1.25 k g / m^{3}$
The rms speed of $N_{2}$ molecules is given by
$V_{r m s} = \sqrt{\frac{3 R T}{M}} = \sqrt{\frac{3 P}{ρ}}$
$V_{r m s} = \sqrt{\frac{3 P}{ρ}}$
$V_{r m s} = \sqrt{\frac{3 \times 1.013 \times 10^{5}}{1.25}} = 493 m / s$
The correct option is A.

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Similar questions

Calculate the rms speed of nitrogen at STP (pressure = 1 atm and temperature = $0^{\circ} C$ ). The density of nitrogen in these conditions is $1.25 k g m^{- 3}$ .

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The rms speed of N2 molecular at STP (P=1 tm; T=00C) is.....(the density of N2 in these conditions is 1.25 kg/m3

The correct option is A 493 m/sGiven,P=1.013×105PaT=273.15Kρ=1.25kg/m3The rms speed of N2 molecules is given byVrms=√3RTM=√3PρVrms=√3PρVrms=√3×1.013×1051.25=493m/sThe correct option is A.

The rms speed of $N_{2}$ molecular at STP (P=1 tm; T= $0^{0} C$ ) is.....
(the density of $N_{2}$ in these conditions is 1.25 ${k g / m}^{3}$