Question

Calculate the slope and $y$-intercept of the line $x-3y+1=0$

Answer 1

Given:$x-3y+1=0$

$\Rightarrow 3y=x+1$

$\Rightarrow y=\frac{1}{3}x+\frac{1}{3}$

Comparing with $y=mx+c$, we get

$m=\frac{1}{3},c=\frac{1}{3}$

$\therefore$Slope$=\frac{1}{3},y$-intercept$=\frac{1}{3}$