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Heat of Formation

Calculate the...

Question

Calculate the standard internal energy of formation of liquid methyl acetate $(C H_{3} C O O C H_{3})$ from its standard enthalpy of formation, which is $- 442.91 k J m o l e^{- 1} a t 25^{\circ} C .$ :

A

- 442.91

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B

+ 442.91

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C

- 452.82

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D

452.82

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Solution

The correct option is A $- 442.91$
$H$ = $U$ + $P V$
If volume changes is zero then
$P V$ = $0$
$H$ = $U$
Where $H$ = Enthalpy
$U$ = Internal energy

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