Calculate the sum:
a + 2ab + 4ba + 6b =

a + 6b (a + 1)

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b + 6b (a + 1)

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a + 6b (a + 1)

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Solution

The correct option is C a + 6b (a + 1)

a + 2ab + 4ba + 6b
= a + 6ab + 6b
= a + 6b (a + 1)

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∣ ∣ ∣ ∣ \begin{matrix} a + b & a + 2 b & a + 3 b a + 2 b & a + 3 b & a + 4 b a + 4 b & a + 5 b & a + 6 b \end{matrix} ∣ ∣ ∣ ∣ =

∣ ∣ ∣ ∣ \begin{matrix} a + b & a + 2 b & a + 3 b a + 2 b & a + 3 b & a + 4 b a + 4 b & a + 5 b & a + 6 b \end{matrix} ∣ ∣ ∣ ∣

$2 a b + 3 b c + 4 b a - 2 c b + 3 a b + 8 b c$ equals

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