Calculate the sum of lone pairs of electrons in the central atoms of the molecules $X e O F_{4}, [X e O_{6}]^{4 -}$ and $C l F_{3}$ .

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Solution

The central atom of $X e O F_{4}$ is $X e$ . The total number of lone pairs of electrons in $X e$ of $X e O F_{4}$ is 1.

The central atom of $[X e O_{6}]^{4 -}$ is $X e$ and the total number of lone pairs of electrons in $X e$ of $[X e O_{6}]^{4 -}$ is 0.

The central atom of $C l F_{3}$ is $C l$ and the total number of lone pairs of electrons in $C l$ of $C l F_{3}$ is 2.

So, the required sum of lone pairs of electrons in the central atoms is $2 + 1 = 3$

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