The correct option is C 1770
The common difference of the given arithmetic series is 4.
The number of terms of the given A.P. series (n) = 30
S=n2[2a+(n−1)d]
Therefore, the required sum of first 30 terms of the series,
S=302[2×1+(30−1)4]
S=302[2+116]
S=15[118]
S=1770