Question

Calculate the tension in the string shown in figure. The pulley and the string are light and all surfaces are frictionless. Take $g=10m/s^2$.

Answer 1

$FBD$ of $B$.

For $B$, By newton's $2^{nd}$ law

$T+1a=19---\left(1\right)$

For $A(m=110g)$,

$T=ma---\left(2\right)$

$T=ma$

$\therefore 2a=ga=\frac{10}{2}=5m/s^2$