Question

Calculate the total energy of one mole of an ideal mono atomic gas at ${27}^o$C.

• A. $900cal$
• B. $1800cal$
• C. $7482cal$
• D. $0cal$

Answer 1

The correct option is A $900cal$

The total energy of one mole of an ideal mono atomic gas at ${27}^o$C is

$E=\frac{3}{2}nRT$

$E=\frac{3}{2}\times 1mol\times 2cal/K/mol\times (27+273)K$

$E=900cal$