Calculate the total n-factor for the oxidation half reaction given below: FeC2O4(aq)→Fe3+(aq)+CO2(g)
A
2
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B
1
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C
3
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D
4
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Solution
The correct option is C 3 For the given reaction : +2Fe+3C2O4(aq)⟶Fe3+(aq)+CO2(g)
Oxidation : Fe2+⟶Fe3+ nf=|2−3|×1=1
Oxidation : +3C2O2−4⟶+4CO2 nf=|3−4|×2=2 (nf)T=(nf)Fe+(nf)C=2+1=3