Question

Calculate the total no. Of phenotypes and genotypes in the polygenic between cross AaBbCcDd and AaBbCcDd?

Answer 1

Dear Student,

In a polygenic inheritance,
The number of genotypes can be calculated as 3ⁿ and the number of phenotypes can be calculated as 2ⁿ where 'n' represent the number of heterozygotes.
In the given cross, there are 4 types of heterozygotes i.e Aa, Bb, Cc and Dd.
Therefore,
Number of genotypes = 3⁴ = 81
Number of phenotypes = 2⁴ = 16

Regards