Question

calculate the total number of electrons present in 1.6g of methane

Answer 1

Dear User,
Molecular mass of methane (CH₄) = 12 + 4 = 16 g
$$\begin{gathered} \mathrm{Number}\mathrm{of}\mathrm{moles}\mathrm{in}1.6\mathrm{g}\mathrm{of}\mathrm{methane}=\frac{1.6}{16}=0.1 \\ \mathrm{Number}\mathrm{of}\mathrm{molecules}\mathrm{of}\mathrm{methane}\mathrm{in}0.1\mathrm{mole}=0.1\times 6.023\times {10}^{23}=6.023\times {10}^{22} \\ \mathrm{One}\mathrm{molecule}\mathrm{of}\mathrm{methane}\mathrm{has}=6+4=10\mathrm{electrons} \\ \mathrm{So},6.023\times {10}^{22}\mathrm{molecules}\mathrm{of}\mathrm{methane}\mathrm{have}=10\times 6.023\times {10}^{22}\mathrm{electrons} \\ =6.023\times {10}^{23}\mathrm{electrons} \end{gathered}$$