Question

Calculate the total number of unpaired electrons in [Cr(H${}_2$O)${}_6$]${}^{3+}$.

Answer 1

$\left[Cr\right(H_{2}O{)}_6{]}^{3+}$ has three unpaired electrons. It has $3d^3$ outer electronic configuration which can also be written as $t_{2g}^3{e}_g^0$.