Calculate the value of gravitational force between two objects of mass of 40 kg each, separated by a distance of 0.4 m. Take G = 6.7 x 10^-11 Nm² kg^-2.

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Solution

Given:
The masses of two objects. i.e., m₁ = 40 kg, m₂ = 40 kg.
Distance between the two objects (R) = 0.4 m.
The universal gravitational constant G = 6.7 x 10^-11 Nm² kg^-2.
Required to find:
The value of gravitational force (F) between the two objects.
Solution:
The magnitude of the gravitational force of attraction between two bodies is given by $F = \frac{G m_{1} m_{2}}{{(R)}^{2}}$ .
By substituting the given values in the above equation, $F = \frac{(6.7 x 10^{- 11}) x (40) x (40)}{{(0.4)}^{2}} = \frac{10, 720 x 10^{- 11}}{0.16} = 67, 000 x 10^{- 11} = 6.7 x 10^{- 7} N$
Hence, the value of the gravitational force between the two objects is $6.7 x 10^{- 7} N$

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Calculate the value of gravitational force between two objects of mass of 40 kg each, separated by a distance of 0.4 m. Take G = 6.7 x 10-11 Nm2 kg-2.

Calculate the value of gravitational force between two objects of mass of 40 kg each, separated by a distance of 0.4 m. Take G = 6.7 x 10^-11 Nm² kg^-2.