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Question

Calculate the variance and standard deviation of the following continuous frequency distribution
Class interval 30404050506060707080809090100
Frequency 371215832

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Solution

Class Interval Mid Value (x) frequency (f) fx fx2
3040 35 3 105 3675
4050 45 7 315 14175
5060 55 12 660 36300
6070 65 15 957 63375
7080 75 8 600 45000
8090 85 3 255 21675
90100 95 2 190 18050
n=f=50
¯x=1nfxi=308250=61.64
Variance (σ2)=1nfx2(¯x)2=20225050(61.64)2=245.5104
Standard deviation (σ)=245.5104=15.67

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