Question

Calculate the volume occupied by $5.25g$ of nitrogen at ${26}^{o}C$ and $74\cdot 2cm$ of pressure.

Answer 1

P$=\frac{74.2}{76}atm$

V$=?$

m$=5.25g$

M$=28g$

T$=273+26=299K$

$PV=nRT$

$\frac{74.2}{76}\times V=\frac{m}{M}\times 0.0821\times 299$

$V=\frac{5.25}{28}\times 0.0821\times 299\times \frac{76}{74.2}$

$V=4.7107L$