Calculate the volume occupied by 8-8 g of CO 2 at 31-1- C and 1 bar pressure- R -0-083 bar LK -1 mol -1

It is known that, pV=m/MRT ⇒ V=mRT/Mp Here, m= 8.8 g R = 0.083 bar LK^ 1 mol^ 1 T = 31.1^∘ C = 304.1 K M = 44 g p = 1 bar Thus, volume (V)=8.8× 0.083×304 ...

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Standard XII

Chemistry

Ideal Gas Equation

Calculate the...

Question

Calculate the volume occupied by 8.8 g of $C O_{2}$ at ${31.1}^{\circ} C$ and 1 bar pressure.
$R = 0.083 b a r L K^{- 1} m o l^{- 1}$
.

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Solution

It is known that,
$p V = \frac{m}{M} R T \Rightarrow V = \frac{m R T}{M p}$
Here, $m = 8.8 g R = 0.083 b a r L K^{- 1} m o l^{- 1} T = {31.1}^{\circ} C = 304.1 K M = 44 g p = 1 b a r$
Thus, volume $(V) = \frac{8.8 \times 0.083 \times 304.1}{44 \times 1} = 5.04806 L = 5.05 L$
Hence, the volume occupied is 5.05 L.

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Ideal Gas Equation

Standard XII Chemistry

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Calculate the volume occupied by 8.8 g of CO2 at 31.1∘C and 1 bar pressure. R=0.083 bar LK−1 mol−1 .

It is known that, pV=mMRT⇒V=mRTMp Here, m=8.8gR=0.083bar LK−1mol−1T=31.1∘C=304.1 KM=44gp=1 bar Thus, volume (V)=8.8×0.083×304.144×1=5.04806 L=5.05 L Hence, the volume occupied is 5.05 L.

Calculate the volume occupied by 8.8 g of $C O_{2}$ at ${31.1}^{\circ} C$ and 1 bar pressure.
$R = 0.083 b a r L K^{- 1} m o l^{- 1}$
.