Calculate the volume of 0.005M KMnO4solution required to oxidise completely 2.7g of oxalic acid(H2C2O4) in acidic medium.According to equation 2KMnO4 +3H2SO4+5C2H2O4->K2SO4 +2MnSO4 +8H20 + 10CO2

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K M n O_{4} + H_{2} S O_{4} + H C l \to K_{2} S O_{4} + M n S O_{4} + C l_{2} + H_{2} O

2 K M n O_{4} + 5 H_{2} C_{2} O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 10 C O_{2} + 8 H_{2} O

M n S O_{4}

1.5

K M n O_{4}, 3.5 m o l

H_{2} C_{2} O_{4}

2.5

H_{2} S O_{4}

2 K M n O_{4} + 3 H_{2} S O_{4} ⟶ K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 (O)

K M n O_{4}

K M n O_{4} = 158

K M n O_{4}

K M n O_{4}

C O_{2}

l i t r e

10^{- 4} M K M n O_{4}

0.5 l i t r e

10^{- 2} M

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