Question

Calculate the volume of 0.1 N NaOH required for neutralising the solution obtained by mixing 10 mL of 0.1 N $H_{2}S{O}_4$ and 10 ml of 0.1 N HCl.

• A.
  10 mL
• B.
  20 mL
• C.
  40 mL
• D. 30 mL

Answer 1

The correct option is B

20 mL
In any acid base titration, the number of equivalents of the acids and the bases are equal.
Milliequivalent of the acids = $\text{volume in mL}\times \text{normality}$
$=10\times 0.1N{H}_{2}S{O}_4+10\times 0.1NHCl=2$
Volume of NaOH = $\frac{\text{milliequivalents}}{\text{normality}}=\frac{2}{0.1}=20mL$