Question

Calculate the volume of $80$% $H_{2}S{O}_4$ by weight (density $=1.80gm{L}^{-1}$) required to prepare $1L$ of $0.2M{H}_{2}S{O}_4$.

• A. 8.98 ml
• B. 13.62 ml
• C. 14.48 ml
• D. 10.24 ml

Answer 1

The correct option is B 13.62 ml

$\begin{array}{cc}& \begin{array}{cc}\text{Molarity}& =\frac{\text{Percentage by mass}\times 10\times \text{density}}{\text{Molar mass}}\\ & =\frac{80\times 10\times 1.8}{98}\\ & =14.69mol{L}^{-L}\end{array}\\ & \begin{array}{c}\Rightarrow \text{IJsing Molarity equation,}\\ M_1{V}_1=M_2{V}_2\end{array}\\ & \begin{array}{c}\Rightarrow 14.69V_1=0.2\times 1000\\ \therefore V_1=0.0136L\\ \Rightarrow V_1=13.6mL\end{array}\end{array}$