1
Question
Calculate the volume of CO2 gas obtained on the complete combustion of 30 mL of propane gas at STP:
Calculate the volume of CO2 gas obtained on the complete combustion of 30 mL of propane gas at STP:
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Solution
The correct option is C 90 mL
Combustion of propane:
C3H8(g)+5O2(g)→3CO2(g)+4H2O(l)
Gay-Lussac’s law of combining volume states that when gases react, they do so in volumes which bear a simple ratio to one another, and to the volume of the product(s) formed if gaseous, provided the temperature and pressure conditions remain constant. In the above equation:
1 volume of propane yields 3 volumes of CO2
So, 30 mL propane yields =3×30 mL of CO2=90 mL CO2
Combustion of propane:
C3H8(g)+5O2(g)→3CO2(g)+4H2O(l)
Gay-Lussac’s law of combining volume states that when gases react, they do so in volumes which bear a simple ratio to one another, and to the volume of the product(s) formed if gaseous, provided the temperature and pressure conditions remain constant. In the above equation:
1 volume of propane yields 3 volumes of CO2
So, 30 mL propane yields =3×30 mL of CO2=90 mL CO2
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